By diagonal relationship,the acid formed by $S i$ similar to boric acid being formed by boron has the formula:

H_{3} S i O_{3}

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H_{2} S i O_{3}

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H_{3} S i O_{4}

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H S i O_{4}

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Solution

The correct option is C $H_{2} S i O_{3}$
Silicon forms a weak acid having formula $H_{2} S i O_{3}$ .

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Similar questions

Q. Which of the following statements are correct ?

(i) Boron reacts with concentrated

H N O_{3}

to form nitric oxide and boric acid
(ii) Boron reacts with fused

N a O H

to form

H_{2} O_{2}

and boric acid
(iii) Boron reacts with

S i O_{2}

to form

S i

and

B_{2} O_{3}

Q. Assertion :Be is readily attacked by acids. Reason: Be shows diagonal relationship to Na.

Q. How to get elemental boron from boric acid

A solution of 10% boric acid is to be diluted by adding a 4% boric acid solution to it. The resulting mixture is to be more than 5% but less than 8% boric acid. If we have 750 litres of the 10% solution, then the quantity of the 4% solution that has to be added will lie between

Q. The correct formula of salt formed by the neutralization hypophosphorous acid with

N a O H

is:

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By diagonal relationship,the acid formed by Si similar to boric acid being formed by boron has the formula:

The correct option is C H2SiO3Silicon forms a weak acid having formula H2SiO3.

By diagonal relationship,the acid formed by $S i$ similar to boric acid being formed by boron has the formula:

The correct option is C $H_{2} S i O_{3}$
Silicon forms a weak acid having formula $H_{2} S i O_{3}$ .