By driving at 4/5^th of my usual speed, I reach my office 10 minutes later than usual. What is my usual time of travel (in minutes)?

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Solution

The correct option is C
40

Let the usual speed be 'v' and the usual time be 't'.

Now in both the scenario, distance between me and my office is same.

v * t = 4/5v * ( t + 10)

5t = 4t + 40

t = 40 minutes

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