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Question

By eliminating θ, from x=acos3θ,y=asin3θ,the expression is

A
x+y=a
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B
x2+y2=a2
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C
x2/3+y2/3=a2/3
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D
none of the above
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Solution

The correct option is C x2/3+y2/3=a2/3
x=acos3θ
(xa)13=cosθ
Similarly (ya)13=sinθ
We know, sin2θ+cos2θ=1
(ya)23+(xa)23=1
Hence,
y23+x23=a23
Hence, option 'C' is correct.

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