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Question

By following these steps of construction,

(i) Draw a line segment PQ = 11 cm

(ii) At P construct an angle of 60o and at Q, an angle of 45o.

(iii) Bisect these angles. Let the bisectors of these angles intersect at a point A.

(iv) Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C.

(v). Join AB and AC. Triangle ABC has been obtained. In this ∆ABC,

A
AB + BC + CA > 11cm
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B
AB + BC = 11cm
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C
AB + BC + CA = 11cm
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D
BC + CA = 11cm
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Solution

The correct option is C AB + BC + CA = 11cm
AB + BC + CA = 11cm

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