By following these steps of construction,
(i) Draw a line segment PQ = 11 cm
(ii) At P construct an angle of 60o and at Q, an angle of 45o.
(iii) Bisect these angles. Let the bisectors of these angles intersect at a point A.
(iv) Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C.
(v). Join AB and AC. Triangle ABC has been obtained. In this ∆ABC,