By how much is $5 a^{2} b^{2} - 18 a b^{2} - 10 a^{2} b$ bigger than $- 5 a^{2} + 6 a^{2} b - 7 a b$ $[2 M a r k s]$

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Solution

The required result is,

$(5 a^{2} b^{2} - 18 a b^{2} - 10 a^{2} b) - (- 5 a^{2} + 6 a^{2} b - 7 a b)$

= $5 a^{2} b^{2} - 18 a b^{2} - 10 a^{2} b + 5 a^{2} - 6 a^{2} b + 7 a b$ $[1 M a r k]$

= $5 a^{2} b^{2} - 18 a b^{2} - 10 a^{2} b - 6 a^{2} b + 5 a^{2} + 7 a b$

= $5 a^{2} b^{2} - 18 a b^{2} - 16 a^{2} b + 5 a^{2} + 7 a b$ $[1 M a r k]$

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By how much is $5 a^{2} b^{2} - 18 a b^{2} - 10 a^{2} b$ bigger than $- 5 a^{2} + 6 a^{2} b - 7 a b$

5 a^{2} - 7 a b + 5 b^{2}

3 a b - 2 a^{2} - 2 b^{2}

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