By how much is $5 a^{2} b^{2} - 18 a b^{2} - 10 a^{2} b$ bigger than $- 5 a^{2} + 6 a^{2} b - 7 a b$ ?

$5 a^{2} b^{2} - 18 a b^{2} - 16 a^{2} b + 5 a^{2} - 7 a b$

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$5 a^{2} b^{2} - 18 a b^{2} - 16 a^{2} b - 5 a^{2} + 7 a b$

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$5 a^{2} b^{2} + 18 a b^{2} + 16 a^{2} b - 5 a^{2} - 7 a b$

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$5 a^{2} b^{2} - 18 a b^{2} - 16 a^{2} b + 5 a^{2} + 7 a b$

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Solution

The correct option is D
$5 a^{2} b^{2} - 18 a b^{2} - 16 a^{2} b + 5 a^{2} + 7 a b$

The required result is,

$(5 a^{2} b^{2} - 18 a b^{2} - 10 a^{2} b) - (- 5 a^{2} + 6 a^{2} b - 7 a b)$

$= 5 a^{2} b^{2} - 18 a b^{2} - 10 a^{2} b + 5 a^{2} - 6 a^{2} b + 7 a b$

$= 5 a^{2} b^{2} - 18 a b^{2} - 10 a^{2} b - 6 a^{2} b + 5 a^{2} + 7 a b$

$= 5 a^{2} b^{2} - 18 a b^{2} - 16 a^{2} b + 5 a^{2} + 7 a b$

Suggest Corrections

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Subtract:

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