By how much is 5a2b2−18ab2−10a2b greater than −5a2+6a2b−7ab?
5a2b2−18ab2−16a2b+5a2+7ab
The required result is,
(5a2b2−18ab2−10a2b)−(−5a2+6a2b−7ab)
=5a2b2−18ab2−10a2b+5a2−6a2b+7ab
=5a2b2−18ab2−10a2b−6a2b+5a2+7ab
=5a2b2−18ab2−16a2b+5a2+7ab