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Question

By how much is 6a2b2−19ab2−11a2b greater than −6a2+7a2b−8ab?


A

h+r

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B

h

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C
2h
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D
All of the above
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Solution

The correct option is B

h


The required result is,

(6a2b219ab211a2b)(6a2+7a2b8ab)

=6a2b219ab211a2b+6a27a2b+8ab

=6a2b219ab211a2b7a2b+6a2+8ab

=6a2b219ab218a2b+6a2+8ab


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