By how much is $a^{4} + 4 a^{2} b^{2} + b^{4}$ more than $a^{4} - 8 a^{2} b^{2} + b^{4}$ ?

12 a^{2} b^{2}

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- 12 a^{2} b^{2}

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2 a^{4} + 2 b^{4}

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10 a^{2} b^{2}

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Solution

The correct option is A $12 a^{2} b^{2}$
Required expression
= ( $a^{4} + 4 a^{2} b^{2} + b^{4}$ ) - ( $a^{4} - 8 a^{2} b^{2} + b^{4}$ )
= $a^{4} + 4 a^{2} b^{2} + b^{4} - a^{4} + 8 a^{2} b^{2} - b^{4}$
= $12 a^{2} b^{2}$

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G . P

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A . P

G . P

b_{1}, b_{2}, b_{3}, b_{4}

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