By how much must $2 p^{2} q^{2} - 3 p^{2} q + 4 p q$ be increased to get $8 p^{2} q^{2} + 4 p^{2} q - 3 p^{2} q - 2 p q + 4 ?$

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Solution

$A = 8 p^{2} q^{2} + 4 p^{2} q - 3 p^{2} q - 2 p q + 4$
$B = 2 p^{2} q^{2} - 3 p^{2} q + 4 p q$

$A - B = 8 p^{2} q^{2} + 4 p^{2} q - 3 p^{2} q - 2 p q + 4 - 2 p^{2} q^{2} + 3 p^{2} q - 4 p q$
$A - B = 6 p^{2} q^{2} + 7 p^{2} q - 3 p^{2} q - 6 p q + 4$

$(6 p^{2} q^{2} + 7 p^{2} q - 3 p^{2} q - 6 p q + 4)$ should be added.

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