By how much will be the potential of a copper electrode change if the solution of $C u S O_{4}$ which is immersed is diluted to 10 times at 298K?

Increases by 30mV

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Decreases by 30mV

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Increases by 60mV

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Decreases by 60mV

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Solution

The correct option is B Decreases by 30mV
The change in electrode potential is given by the expression,
$E_{2} - E_{2} = \frac{0.0592}{2} l o g \frac{C_{2}}{C_{1}}$ .
Substitute values in the above expression
$E_{2} - E_{2} = \frac{0.0592}{2} l o g \frac{0.1}{1} = 30 m V .$

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By how much will the potential of half cell cu+2/Cu change, if the solution is diluted to 100 times at 298 K?

(1) Increases by 59 mV

(2) Decreases by 59 mV

(3) Increases by 29.5 mv

(4) Decreases by 29.5 mV

C u S O_{4}

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