Question

By how much will the total surface area of a cube with side $43$ cm be more than that of a cube with side $26$ cm ?

Answer 1

We have to determine the difference of total surface area of the two cubes.
Let the cube with the side 43 cm be $C_1$ and the cube with the side 26 cm be $C_2$

Total Surface Area of a cube $=6\times s\times s$, where $s$ is the length of its side.

So, for cube $C_1$ with side $43$ cm,
Total surface area $=6\times 43\times 43=6\times 1849=11094$ cm${}^2$

For cube $C_2$ with side $26$ cm,
Total surface area $=6\times 26\times 26=6\times 676=4056$ cm${}^2$

Therefore the difference in the total surface area of two cubes is $=11094-4056=7038$ cm${}^2$