By increasing temperature of a gas by $6$ its pressure increases by $0.4$ at constant volume then initial temperature of gas is.

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Solution

From ideal gas law, for specific amount of gas , pressure of gas be directly proportional to its temperature at constant volume .
$\frac{P_{2} - P_{1}}{P_{1}} \times 100 = \frac{T_{2} - T_{1}}{T_{1}} \times 100$

or, percentage change in pressure = change in temperature/initial temperature × 100

0.4 = 6/ × 100

= 600/0.4 = 1500°C

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By increasing temperature of a gas by 6 its pressure increases by 0.4 at constant volume then initial temperature of gas is.

From ideal gas law, for specific amount of gas , pressure of gas be directly proportional to its temperature at constant volume . P2−P1P1×100=T2−T1T1×100or, percentage change in pressure = change in temperature/initial temperature × 100 0.4 = 6/ × 100 = 600/0.4 = 1500°C

By increasing temperature of a gas by $6$ its pressure increases by $0.4$ at constant volume then initial temperature of gas is.