Question

By making $I$ as the subject in $T=2\pi \sqrt{\frac{I}{g}}$ we obtain $I=$

• A. $\frac{g{T}^2}{4{\pi }^2}$
• B. $\frac{g{T}^2}{2\pi }$
• C. $\frac{4{\pi }^2}{g{T}^2}$
• D. $\frac{2\pi }{g{T}^2}$

Answer 1

Answer: (A)

$\frac{g{T}^2}{4{\pi }^2}$

$T=2\pi \sqrt{\frac{I}{g}}$
Squaring on both sides, we get
$T^2=4{\pi }^2\left(\frac{I}{g}\right)$
$I=\frac{g{T}^2}{4{\pi }^2}$