Question

By Remainder Theorem find the remainder, when $p\left(x\right)$ is divided by $g\left(x\right)$, where$p\left(x\right)=x^3-2x^2-4x-1$ , $g\left(x\right)=x+1$.

• A. 1
• B. -1
• C. 2
• D. 0

Answer 1

The correct option is D 0

Here $p\left(x\right)=x^3-2x^2-4x-1$ and $g\left(x\right)=x+1$

Now, $p\left(x\right)$ is divided by $g\left(x\right)$

Thus the remainder is $p(-1)$$=(-1{)}^3-2(-1{)}^2-4(-1)-1$ (By Remainder Theorem)
$=-1-2+4-1$
$=0$
Thus, remainder is $0$