Question

By Remainder Theorem find the remainder, when $p\left(x\right)$ is divided by $g\left(x\right)$, where$p\left(x\right)=x^3-3x^2+4x+50andg\left(x\right)=x-3$.

• A. 61
• B. 62
• C. 60
• D. 59

Answer 1

The correct option is B 62

Given $p\left(x\right)=x^3-3x^2+4x+50$ and $g\left(x\right)=x-3$

Here, $p\left(x\right)$ is divided by $g\left(x\right)$

The remainder is $p\left(3\right)$ $=3^3-3(3{)}^2+4\times 3+50$ (By Remainder Theorem)

$=27-27+12+50$

$=62$

Thus, the remainder is $62$