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Question

By Simpson's rule, the value of 33x4dy by taking 6 sub-intervals, is

A
98
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B
90
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C
80
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D
70
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Solution

The correct option is A 98
Here, h=3(3)6=1h=3−(−3)6=1
By Simpson's rule,
33x4dx=13[(81+81)+4(16+0+16)+2(1+1)]∫−33x4dx=13[(81+81)+4(16+0+16)+2(1+1)]
=13[162+128+4]=13[162+128+4]
=2943=2943
=98
Here, h=3(3)6=1h=3−(−3)6=1
By Simpson's rule,
33x4dx=13[(81+81)+4(16+0+16)+2(1+1)]∫−33x4dx=13[(81+81)+4(16+0+16)+2(1+1)]
=13[162+128+4]=13[162+128+4]
=2943=2943
=98

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