wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

By sucking through a straw, a student can reduce the pressure in his lungs to 750 mm of Hg (density 13.6gcm3) using the straw, he can drink water from a glass up to a maximum depth of

A
10.2cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
75.3cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
13.6cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.96cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 13.6cm
Normal pressure is 760mmHg so the boy can create a depression of 10mmHg in his lungs.

According to the law of flotation

Weight of floating body = Weight of displaced liquid

Wt. Of water displaced from glass = Wt of air of lung reduced (interm of mmHg)

Wt of water displaced from glass = density of water (d1)× volume of water displaced (v1)

Wt of air reduce from lung (interm of mmHg) = density of Hg (d2)× volume of air displaced (v2)

Now d1×v1=d2×v2

And v1=d2×v2d1=13.6g/cm3×10mm1g/cm3=136mm=13.6cm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Variation of Pressure in Fluids
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon