By taking two J - tubes at constant temperature, what is the difference in the levels of mercury in two columns?

1013.3 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1140 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

253.3 mm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

760 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
253.3 mm

$P_{1} V_{1} = P_{2} V_{2}$

$h_{1} d g V_{1} = h_{2} d g V_{2}$

$760 \times 2.4 = ⟮ 760 + x ⟯ 1.8 \Rightarrow x = 253.3 m m$

Suggest Corrections

Similar questions

In a constant volume gas thermometer, the pressure of the working gas is measured by the difference in the levels of mercury in the two arms of a U-tube connected to the gas at one end. When the bulb is placed at the room temperature 27.0℃, the mercury column in the arm open to atmosphere stands 5.00 cms above the level of mercury in the other arm. When the bulb is placed in a hot liquid, the difference of mercury levels becomes 45.0 cms. Calculate the temperature of the liquid. (Atmospheric pressure = 75.0 cm of mercury.)

Given J-tube has