By treating methyl alcohol with conc. H2SO4 at 140oC. Which of the following products if formed?
A
Ethene
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B
Dimethyl ether
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C
Methyl ethylether
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D
Ethyne
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Solution
The correct option is B Dimethyl ether Two molecules of methanol, undergo dehydration in the presence of conc.H2SO4 at 140∘C to form Dimethyl ether as: 2CH3OHconc.H2SO4−−−−−−−→140∘CCH3−O−CH3+H2O