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Question

By treating methyl alcohol with conc. H2SO4 at 140oC. Which of the following products if formed?

A
Ethene
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B
Dimethyl ether
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C
Methyl ethylether
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D
Ethyne
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Solution

The correct option is B Dimethyl ether
Two molecules of methanol, undergo dehydration in the presence of conc.H2SO4 at 140C to form Dimethyl ether as:
2CH3OHconc.H2SO4−−−−−−140CCH3OCH3+H2O

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