REF.Image
Let (x1,y2) and (x2,y2) be the Cartesian co-ordinates of the points
P and Q resp preferred to rectangle co-ordinate axis ¯¯¯¯¯¯¯¯¯OX and
¯¯¯¯¯¯¯¯OY and the point R divides the line segment ¯¯¯¯¯¯¯¯PQ interacually in a
given ratio m:n i.e., ¯¯¯¯¯¯¯¯PR:¯¯¯¯¯¯¯¯¯RQ=m:n
Let (x,y) be the required co-ordinate of R. From P,Q and R draw
¯¯¯¯¯¯¯¯PL,¯¯¯¯¯¯¯¯¯QN,¯¯¯¯¯¯¯¯¯RN perpendicular or ¯¯¯¯¯¯¯¯¯OX to cut ¯¯¯¯¯¯¯¯¯RN at S and ¯¯¯¯¯¯¯¯¯¯QM at T.
Thus,
¯¯¯¯¯¯¯¯PS=¯¯¯¯¯¯¯¯¯LN=¯¯¯¯¯¯¯¯¯ON−¯¯¯¯¯¯¯¯OL=x−¯x1
¯¯¯¯¯¯¯¯PT=LN=¯¯¯¯¯¯¯¯¯¯OM−¯¯¯¯¯¯¯¯OL=x2−¯x1
¯¯¯¯¯¯¯¯RS=¯¯¯¯¯¯¯¯¯RN−¯¯¯¯¯¯¯¯SN=¯¯¯¯¯¯¯¯¯RN−¯¯¯¯¯¯¯¯PL=y=¯y1
and ¯¯¯¯¯¯¯¯QT=¯¯¯¯¯¯¯¯¯QN−¯¯¯¯¯¯¯¯¯TN=¯¯¯¯¯¯¯¯¯QN−¯¯¯¯¯¯¯¯PL=y2−y1
Again, ¯¯¯¯¯¯¯¯PR/¯¯¯¯¯¯¯¯¯RQ=m/n
¯¯¯¯¯¯¯¯¯RQ/¯¯¯¯¯¯¯¯PR+1=n/m+1
(¯¯¯¯¯¯¯¯¯RQ+¯¯¯¯¯¯¯¯PR/¯¯¯¯¯¯¯¯PR)=(m+n)/m
¯¯¯¯¯¯¯¯PQ/¯¯¯¯¯¯¯¯PR=(m+n)/m
¯¯¯¯¯¯¯¯PS/¯¯¯¯¯¯¯¯PT=¯¯¯¯¯¯¯¯RS/¯¯¯¯¯¯¯¯QT=¯¯¯¯¯¯¯¯PR/¯¯¯¯¯¯¯¯PQ
Take ¯¯¯¯¯¯¯¯PS/¯¯¯¯¯¯¯¯PT=¯¯¯¯¯¯¯¯PR/¯¯¯¯¯¯¯¯PQ
(x−x1)/(x2−x1)=m(m+n)
x=(mx2+nx1)/(m+n)
Again Take, ¯¯¯¯¯¯¯¯RS/¯¯¯¯¯¯¯¯QT=¯¯¯¯¯¯¯¯PR/¯¯¯¯¯¯¯¯¯RQ
∴[(mx2+nx1)(m+n),(my2+ny1)(m+n)]
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