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Question

By using properties of determinants Find :
∣ ∣0aba0cbc0∣ ∣=0.

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Solution

∣ ∣0aba0cbc0∣ ∣=0
L.H.S0aba0c
Expanding along R1
=00cc0aacb0ba0bc
=0a(0+bc)b(ac0)
=abc+abc
=0.
R.H.S.

1206502_1242801_ans_9d6dcbcdb95e4c359f4b3b513e872f8a.jpg

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