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Question

By using suitable identities, evaluate: (10.1)3

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Solution

(10.1)3

It can be written as

= (10 + 0.1)3

( 0.5 marks )
Expanding using formula

= 103 + 0.13 + 3 × 10 × 0.1 (10 + 0.1)
( 0.5 marks )

By further calculation

= 1000 + 0.001 + 3 × 10.1
( 0.5 marks )

So we get

= 1000 + 0.001 + 30.3

= 1030.301
( 0.5 marks )


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