1
Question
By using suitable identities, evaluate: (10.1)3
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Solution
(10.1)3
It can be written as
= (10 + 0.1)3
( 0.5 marks )
Expanding using formula
= 103 + 0.13 + 3 × 10 × 0.1 (10 + 0.1)
( 0.5 marks )
By further calculation
= 1000 + 0.001 + 3 × 10.1
( 0.5 marks )
So we get
= 1000 + 0.001 + 30.3
= 1030.301
( 0.5 marks )
(10.1)3
It can be written as
= (10 + 0.1)3
( 0.5 marks )
Expanding using formula
= 103 + 0.13 + 3 × 10 × 0.1 (10 + 0.1)
( 0.5 marks )
By further calculation
= 1000 + 0.001 + 3 × 10.1
( 0.5 marks )
So we get
= 1000 + 0.001 + 30.3
= 1030.301
( 0.5 marks )
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