By using the formula, find the amount and compound interest on:

A machine is purchased for Rs 625000. Its value depreciates at the rate of $8 %$ per annum. What will be its value after 2 years ?

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Solution

$Value of machine (P) = Rs. 625000 Rate of depreciation (R) = 8 % p . a . Period (n) = 2 years ∴ Value after 2 years = P {(1 - \frac{R}{100})}^{n} = R s . 625000 {(1 - \frac{8}{100})}^{2} = R s . 625000 {(\frac{23}{25})}^{2} = R s . 625000 \times \frac{23}{25} \times \frac{23}{25} = R s . 529000$

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By using the formula, find the amount and compound interest on: A machine is purchased for Rs 625000. Its value depreciates at the rate of 8% per annum. What will be its value after 2 years ?

Value of machine (P) = Rs. 625000Rate of depreciation (R)=8% p.a.Period (n) = 2 years∴ Value after 2 years= P(1−R100)n=Rs. 625000(1−8100)2=Rs. 625000(2325)2=Rs. 625000×2325×2325=Rs.529000

By using the formula, find the amount and compound interest on:

A machine is purchased for Rs 625000. Its value depreciates at the rate of $8 %$ per annum. What will be its value after 2 years ?

$Value of machine (P) = Rs. 625000 Rate of depreciation (R) = 8 % p . a . Period (n) = 2 years ∴ Value after 2 years = P {(1 - \frac{R}{100})}^{n} = R s . 625000 {(1 - \frac{8}{100})}^{2} = R s . 625000 {(\frac{23}{25})}^{2} = R s . 625000 \times \frac{23}{25} \times \frac{23}{25} = R s . 529000$