By using the formula, find the amount and compound interest on:

A scooter is bout at Rs 56000. Its value depreciates at the rate of $10 %$ per annum. What will be its value after 3 years ?

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Solution

$Value of scooter (P) = Rs. 56000 Rate of depreciation (R) = 10 % p . a . Period = 3 years ∴ Value of scooter after 3 years = P {(1 - \frac{R}{100})}^{n} = R s . 56000 {(1 - \frac{10}{100})}^{3} = R s . 56000 \times \frac{9}{10} \times \frac{9}{10} \times \frac{9}{10} = R s . 40824$

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By using the formula, find the amount and compound interest on: A scooter is bout at Rs 56000. Its value depreciates at the rate of 10% per annum. What will be its value after 3 years ?

Value of scooter (P) = Rs. 56000Rate of depreciation (R)= 10% p.a.Period = 3 years∴ Value of scooter after 3 years= P (1−R100)n=Rs. 56000(1−10100)3=Rs. 56000×910×910×910=Rs. 40824

By using the formula, find the amount and compound interest on:

A scooter is bout at Rs 56000. Its value depreciates at the rate of $10 %$ per annum. What will be its value after 3 years ?

$Value of scooter (P) = Rs. 56000 Rate of depreciation (R) = 10 % p . a . Period = 3 years ∴ Value of scooter after 3 years = P {(1 - \frac{R}{100})}^{n} = R s . 56000 {(1 - \frac{10}{100})}^{3} = R s . 56000 \times \frac{9}{10} \times \frac{9}{10} \times \frac{9}{10} = R s . 40824$