Question

By using the formula, find the amount and compound interest on:

The count of bacteria in a certain experiment was increasing at the rate of $2\%$ per hour. Find the bacteria at the end of 2 hours if the count was initially 500000.

Answer 1

$\text{Initially bactaria = 500000}\text{Increase in bacteria}=2\%\text{per hour}\text{Period (n) = 2 hours}\therefore \text{Bacteria after 2 hours}=P{(1+\frac{R}{100})}^n=500000{(1+\frac{2}{100})}^2=500000\times {\left(\frac{51}{50}\right)}^2=500000\times \frac{51}{50}\times \frac{51}{50}=520200$