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Question

By using the properties of definite integrals, evaluate the integral π2π2sin7xdx

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Solution

Let I=π2π2sin7xdx .......... (1)
As sin7(x)=(sin(x))7=(sinx)7=sin7x,
Therefore, sin7x is an odd function.
It is known that, if f(x) is an odd function, then aaf(x)dx=0
I=π2π2sin7xdx=0

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