By using the vertices of a regular decagon different quadrilaterals are formed. If a quadrilateral is selected then the probability that the selected quadrilateral has no side common with the given regular decagon is

\frac{1}{8}

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\frac{5}{42}

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\frac{1}{7}

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\frac{4}{35}

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Solution

The correct option is B $\frac{5}{42}$
Total number of quadrilaterals are $=^{10} C_{4} = 210$ .
The number of quadrilaterals which has no side common with decagon are
$= \frac{^{10} C_{1} \times^{5} C_{3}}{4} = \frac{10 \times 10}{4} = 25$
Probability $= \frac{25}{210} = \frac{5}{42}$

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By using the vertices of a regular decagon different quadrilaterals are formed. If a quadrilateral is selected then the probability that the selected quadrilateral has no side common with the given regular decagon is

The correct option is B 542Total number of quadrilaterals are =10C4=210. The number of quadrilaterals which has no side common with decagon are =10C1× 5C34=10×104=25 Probability =25210=542

The correct option is B $\frac{5}{42}$
Total number of quadrilaterals are $=^{10} C_{4} = 210$ .
The number of quadrilaterals which has no side common with decagon are
$= \frac{^{10} C_{1} \times^{5} C_{3}}{4} = \frac{10 \times 10}{4} = 25$
Probability $= \frac{25}{210} = \frac{5}{42}$