Question

By what number $(4{)}^{-3}$ be multiplied so that the product become $\frac{1}{16}$?

Answer 1

Let the number to be multiplied be $x$
$\left(4^{-3}\right)\times x=\frac{1}{16}$
$\Rightarrow x=\frac{1}{4^2\times 4^{-3}}$
$\Rightarrow x=\frac{1}{4^{2-3}}$
$\Rightarrow x=\frac{1}{4^{-1}}$
$\Rightarrow x=4$