Question

By what number $\frac{-3}{8}$ be multiplied so that the product is $\frac{33}{32}$ ?

• A. $\frac{11}{4}$
• B. $\frac{4}{11}$
• C. $\frac{-4}{11}$
• D. $\frac{-11}{4}$

Answer 1

The correct option is D

$\frac{-11}{4}$

Let the number be $x$

$\because$ The product of two numbers is $\frac{33}{32}$, one of the number is $\frac{-3}{8}$

$\therefore$ The other number = $\frac{33}{32}$ $÷$ $\frac{-3}{8}$

= $\frac{33}{32}$ $\times$ $\frac{-8}{3}$

= $\frac{-11}{4}$