By what number should $(- 3)^{- 2}$ be multiplied so that the product may be equal to $9$ ?

Open in App

Solution

Let, $x$ be multiplied to $(- 3)^{- 2}$ so that the product is equal to $9$

i.e., $(- 3)^{- 2} \times x = 9$

$⟹ \frac{1}{(- 3)^{2}} \times x = 9$

$⟹ \frac{1}{9} \times x = 9$

$⟹ x = 9 \times 9$

$∴ x = 81$

The required number is $81$

Suggest Corrections

Similar questions

{(\frac{1}{2})}^{- 1}

{(- \frac{4}{7})}^{- 1} ?

By what number should $5^{- 1}$ be multiplied so that the product may be equal to $(- 7)^{- 1} ?$

5^{3}

5^{5}

Question 176

By what number should $(- 8)^{- 3}$ be multiplied so that the product may be equal to $(- 6)^{- 3}$ ?

Join BYJU'S Learning Program