Question

By what per cent is the number of adult males in cities C and D more than that of adult females in the same cities?

• A. $33\%$
• B. $30\%$
• C. $35\%$
• D. $35.9\%$
• E. $40\%$

Answer 1

The correct option is A $33\%$

Percentage of females in city C = 100 - 52 - 13 = 35
Adult males $=71200000\times \frac{52}{100}=37024000$
Adult females $=\frac{71200000\times 35}{100}=24920000$
Percentage of females in city D = 40
Adult males $=\frac{93500000\times 49}{100}=45815000$
Adult females $=\frac{93500000\times 40}{100}=37400000$
Difference $=(37024000+45815000)-(24920000-37400000)=20519000$
$\therefore$ Required percentage $=\frac{20519000}{62320000}\times 100=33\%$