Question

By which congruence rule are $△ACB$ and $△ECD$ congruent?(2 marks)

Answer 1

$Given:EC=AC,DC=BC$

and $\angle DCE=\angle ACB$.

(1 mark)

Here, two sides and one included angle of one triangle are equal to the two sides and included angle of the other triangle.

$\therefore$ $△ACB=△DCE\left(bySAScongruencerule\right)$

(1 mark)