By which of the following methods, $H_{2} O_{2}$ can't be synthesised?

Addition of ice cold H_{2} S O_{4} on B a O_{2}

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Addition of ice cold H_{2} S O_{4} on P b O_{2}

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Aerial oxidation of 2-ethyl anthraquinol

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Electrolysis of (N H_{4})_{2} S O_{4} at a high current density

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Solution

The correct option is B $Addition of ice cold H_{2} S O_{4} on P b O_{2}$
(a) $H_{2} S O_{4} + B a O_{2} \to B a S O_{4} ↓ + H_{2} O_{2}$
(b) $H_{2} S O_{4} + P b O_{2} \to P b S O_{4} ↓ + H_{2} O (P b O_{2} is not a peroxy compound)$
(c) $2-ethylanthraquinol H_{2} o r P d - ---- \to O_{2} (a i r) H_{2} O_{2} + Oxidised product$
(d) Peroxodisulphate, obtained by electrolytic oxidation of acidified sulphate solutions at high current density, on hydrolysis yields hydrogen peroxide.
$(N H_{4})_{2} S O_{4} ⇌ 2 N H_{4}^{+} + S O_{4}^{2 -}$
At anode :
$2 S O_{4}^{2 -} Electrolysis - ------ \to S_{2} O_{8}^{2 -} + 2 e^{-}$
$S_{2} O_{8}^{2 -} (a q) H y d r o l y s i s - ----- \to 2 H S O_{4}^{-} (a q) + 2 H^{+} (a q) + H_{2} O_{2} (a q)$
Peroxoxulphate on hydrolysis, produces $H_{2} O_{2}$ .

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Similar questions

Which of the following methods can produce $H_{2} O_{2}$ ?

P b S + H_{2} O_{2} \to P b S O_{4} + H_{2} O

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