By which of the following reactions borazine is prepared?

B_{2} H_{6} + N H_{3} (excess) low temperature - -------- \to

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B_{2} H_{6} + N H_{3} (excess) high temperature - ----------------- \to Higher temperature (> 200^{o} C)

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B_{2} H_{6} + N H_{3} high temperature (200^{o} C) - -------------- \to r a t i o 2 N H_{3} : 1 B_{2} H_{6}

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None of these

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Solution

The correct option is C $B_{2} H_{6} + N H_{3} high temperature (200^{o} C) - -------------- \to r a t i o 2 N H_{3} : 1 B_{2} H_{6}$
$B_{2} H_{6} + N H_{3} (excess) low temperature - -------- \to B_{2} H_{6} .2 N H_{3} o r [H_{2} B (N H_{3})_{2}]^{+} [B H_{4}]^{-}$

$B_{2} H_{6} + N H_{3} (excess) high temperature - ----------------- \to Higher temperature (> 200^{o} C) (B N)_{X} boron nitride$

$B_{2} H_{6} + N H_{3} high temperature(200^oC) - --------------- \to r a t i o 2 N H_{3} : 1 B_{2} H_{6} B_{3} N_{3} H_{6} borazine$
Hence correct option is c.

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