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Trend in Ionisation Enthalpy

By which of t...

Question

By which of the following reactions can $M I C$ (methyl isocyanate) be obtained?

{C H}_{3} - \oplus N \equiv ⊖ C + H g O ⟶

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{C H}_{3} - \oplus N \equiv ⊖ C + O_{3} ⟶

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{C H}_{3} - \oplus N \equiv ⊖ C + S ⟶

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{C H}_{3} - \oplus N \equiv ⊖ C + D M S O ⟶

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Solution

The correct options are
A ${C H}_{3} - \oplus N \equiv ⊖ C + H g O ⟶$
B ${C H}_{3} - \oplus N \equiv ⊖ C + O_{3} ⟶$
D ${C H}_{3} - \oplus N \equiv ⊖ C + D M S O ⟶$
Reactions:
${C H}_{3} - \oplus N \equiv ⊖ C + H g O ⟶ C H_{3} - N = C = O$
${C H}_{3} - \oplus N \equiv ⊖ C + O_{3} ⟶ C H_{3} - N = C = O$
${C H}_{3} - \oplus N \equiv ⊖ C + D M S O ⟶ C H_{3} - N = C = O$

Suggest Corrections

Similar questions

(A)

C H_{3} C H_{2} N H_{2}

(B)

C H_{3} C H_{2} C H_{2} C H_{3} | N H

(C)

H_{3} C - C H_{3} | N - C H_{3}

(D)

P h - C H_{3} | N - H

I . H N = C = O \leftrightarrow H - O - C \equiv N

I I . ¯ N = C = O \leftrightarrow N \equiv C - O^{-}

I I I . C H_{3} - O | | C - ¯ C H_{2} \leftrightarrow C H_{3} -^{-} C = C H_{2}

I V . C H_{3} - O | | C - C H_{3} \leftrightarrow C H_{3} - O H | C = C H_{2}

C H_{3} - O | | C - C H_{3}

X_{2}, O H^{-} - ---- \to

C H_{3} - O | | C - C H_{3}

\to X_{3} C - O | | C - C X_{3}

C H_{3} - O | | C - C H_{3}

O H^{-} - -- \to

C H_{3} - O | | C - O^{-} - C H X_{3}

C H_{3} - C \equiv N + H_{2} O \to

C H_{3} - C H_{3} | C | C H_{3} - C H_{3}

C H_{3} - C H | C H_{3}

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H_{3}

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