By which of the following reactions is borazine prepared?

B_{2} H_{6} + {N H}_{3} (e x c e s s) l o w t e m p e r a t u r e - --------- \to

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B_{2} H_{6} + {N H}_{3} (e x c e s s) h i g h t e m p e r a t u r e - --------- \to

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B_{2} H_{6} + {N H}_{3} h i g h t e m p r a t u r e - ----------- \to r a t i o : 2 {N H}_{3} : 1 B_{2} H_{6}

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None of these

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Solution

The correct option is B $B_{2} H_{6} + {N H}_{3} h i g h t e m p r a t u r e - ----------- \to r a t i o : 2 {N H}_{3} : 1 B_{2} H_{6}$
Inorganic benzene is prepared by the reaction:
$3 B_{2} H_{6} + 6 N H_{3} \to 3 [B H_{2} (N H_{3})_{2}]^{+} [B H_{4}]^{-} H e a t - -- \to 2 B_{3} N_{3} H_{6} + 12 H_{2}$

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Similar questions

6 L i H + {8 B F}_{3} ⟶ {6 L i B F}_{4} + B_{2} H_{6}

2.0

L i H

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B_{2} H_{6}

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B, A l, B_{2} H_{6}, B_{2} O_{3}, N a A l H_{4}, {A l}_{2} O_{3}, A l {C l}_{3}, {B F}_{3}

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