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Byju's Answer
Standard XII
Mathematics
Series
C0.C2 + C1.C3...
Question
C
0
.
C
2
+
C
1
.
C
3
+
C
2
.
C
4
+
.
.
.
.
.
.
.
.
+
C
n
−
2
.
C
n
A
(
2
n
+
1
)
!
(
n
−
1
)
!
(
n
+
2
)
!
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B
(
2
n
)
!
(
n
−
3
)
!
(
n
+
3
)
!
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C
(
2
n
)
!
(
n
−
2
)
!
(
n
+
2
)
!
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D
None
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Solution
The correct option is
D
(
2
n
)
!
(
n
−
2
)
!
(
n
+
2
)
!
We have
C
o
+
C
1
x
+
C
2
x
2
+
.
.
.
.
.
+
C
n
x
n
=
(
1
+
x
)
n
……..
(
1
)
Also
C
o
x
n
+
C
2
x
n
−
2
+
.
.
.
.
.
+
C
n
=
(
x
+
1
)
n
……..
(
2
)
Multiplying
(
1
)
&
(
2
)
(
C
o
+
C
1
x
+
C
2
x
2
+
.
.
.
.
.
+
C
n
x
n
)
×
(
C
o
x
n
+
C
2
x
n
−
2
+
.
.
.
.
+
C
n
)
=
(
1
+
x
)
2
n
………..
(
3
)
Equating coefficients of
x
n
−
r
from both sides of
(
3
)
, we get
C
o
C
r
+
C
1
C
r
+
1
+
C
2
C
r
+
2
+
.
.
.
.
.
+
C
n
−
r
C
n
=
2
n
C
n
−
r
=
(
2
n
)
!
(
n
−
r
)
!
(
n
+
2
)
!
2
n
C
n
−
2
=
(
2
n
)
!
(
n
−
2
)
!
(
n
+
2
)
!
Option C is correct.
Suggest Corrections
0
Similar questions
Q.
Prove that
C
0
+
C
1
2
+
C
2
3
+
C
3
4
+
.
.
.
.
+
C
n
n
+
1
=
2
n
+
1
−
1
(
n
+
1
)
Q.
If
C
0
,
C
1
,
C
2
,
.
.
.
.
.
.
.
.
.
.
.
C
n
are the Binomial coefficients in the expansion
(
1
+
x
)
n
.
‘n’ being even, then
C
0
+
(
C
0
+
C
1
)
+
(
C
0
+
C
1
+
C
2
)
+
.
.
.
.
.
.
.
.
.
(
C
0
+
C
1
+
C
2
+
.
.
.
.
.
+
C
n
−
1
)
=is equal to
Q.
If
n
C
0
2
n
+
2.
n
C
1
2
n
+
3.
n
C
2
2
n
+
…
.
(
n
+
1
)
n
C
n
2
n
=
16
, then the value of '
n
' is:
Q.
2.
C
0
+
2
2
.
C
1
2
+
2
3
.
C
2
3
+
.
.
.
+
2
n
+
1
.
C
n
n
+
1
=
Q.
c
0
,
c
1
,
c
2
denotes coefficents expansion of
(
1
+
x
)
n
, then
c
1
+
c
1
c
2
+
c
2
c
3
+
.
.
.
.
.
.
.
c
n
−
1
c
n
=
(
2
n
)
!
(
n
+
1
)
!
(
n
−
1
)
!
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