You visited us 1 times! Enjoying our articles? Unlock Full Access!

Glycoside Formation

C2H2→ Cis-2-b...

Question

$C_{2} H_{2} \to$ Cis-2-butene

The reagents mentioned below are required to undertake the given reaction.

$R e a g e n t s$ : 1. excess $N a N H_{2}$ 2. excess MeBr 3. $H_{2} / P t$

If true enter 1, if false enter 0.

Open in App

Solution

$C_{2} H_{2} N a N H_{2} - ---- \to E x c e s s C^{-} \equiv C^{-} C H_{3} B r - --- \to E x c e s s C H_{3} C \equiv C C H_{3} H B r - --- \to E x c e s s C H_{3} C H = C H C H_{3} (c i s)$

Excess of soda amide abstracts 2 acidic H atoms from acetylene.
This is followed by reaction with 2 moles of methyl bromide to form 3-butyne.
In the final step, hydrogenation with Lindlar's catalyst forms cis-2-butene. $H_{2} / P t$ cannot be used as the hydrogenation proceeds further to form butane.

Suggest Corrections

Similar questions

C_{2} H_{2} \to

T r a n s - 2 - p e n t e n e

R e a g e n t s

N a N H_{2}

N a N H_{2}

H_{2} / L i n d l a r^{'} s c a t a l y s t

C_{2} H_{2} \to

R e a g e n t s

N a N H_{2}

R e a g e n t s

N a N H_{2}

H_{2} / L i n d l a r^{'} s c a t a l y s t

B_{2} H_{6} / N a O H

R e a g e n t

N a N H_{2}

H_{2} / P t

N a N H_{2}

Join BYJU'S Learning Program