$C_{2} H_{4}$ and $C_{2} H_{2}$ can be distinguished by:

decolourisation of red colour of

B r_{2}

C C l_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

hydrogenation

No worries! We‘ve got your back. Try BYJU‘S free classes today!

with

N a

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

combustion

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C with $N a$
Both $C_{2} H_{4}$ and $C_{2} H_{2}$ are unsaturated compounds so they both react with $B r_{2}$ in $C C l_{4}$ and decolourise it.
But Na reacts with acidic hydrogen and alkene dont have acidic hydrogen so alkene doesnt react with Na.

Suggest Corrections

Similar questions

Complete and balance the following equations. State the conditions wherever necessary.
(a) $C H \equiv C H + H_{2} \to$ ______ $+ H_{2} \to$ _________
(b) $C_{2} H_{4} + B r_{2} \to$ _________
(c) $C_{2} H_{4} + H C l \to$ _________
(d) $C a C_{2} + H_{2} O \to$ _________
(e) $C_{2} H_{2} + B r_{2} \to$ _________
(f) $C_{2} H_{5} O H [O] - ---- \to K_{2} C r_{2} O_{7}$ _________