Question

$C_2{H}_{5}OH+4I_2+3{Na}_{2}C{O}_3\to X+HCOONa+5NaI+3C{O}_2$$+2H_{2}O$
In the above reaction ${}^{\prime }{X}^{\prime }$ is :

• A. Di iodo methane
• B. Tri iodo methane
• C. Iodo methane
• D. Tetra iodo methane

Answer 1

Answer: (B)

Tri iodo methane

The balanced complete reaction is as follows:
$C_2{H}_{5}OH+4I_2+3N{a}_{2}C{O}_3\to X+HCOONa+5NaI+3C{O}_2+2H_{2}O$
In the above reaction X is Tri iodo methane.
$C_2{H}_{5}OH+4I_2+3N{a}_{2}C{O}_3\to CH{I}_3+HCOONa+5NaI+3C{O}_2+2H_{2}O$