$C_{2} H_{5} O H + S O C l_{2} P y r i d i n e ⟶ x + y + z$

In the above given reaction $x, y$ and $z$ respectively are:

C_{2} H_{4} C l_{2}, S O_{2}, H C l

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C_{2} H_{5} C l, S O_{2}, H C l

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C_{2} H_{5} C l, S O C l, H C l

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C_{2} H_{4}, S O_{2}, C l_{2}

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Solution

The correct option is B $C_{2} H_{5} C l, S O_{2}, H C l$
By this reaction pure, alkyl halide forms as a product, because other formed products are gaseous.

The reaction is:
$C_{2} H_{5} O H + S O {C l}_{2} P y r i d i n e - ---- \to C_{2} H_{5} C l + {S O}_{2} + H C l$

Option B is correct.

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Similar questions

C_{2} H_{5} O H + S O C l_{2} P y r i d i n e - ---- \to x + y + z .

C H_{4}

S O_{2}

$A + {S O C l}_{2}$ $\to$ $B + {S O}_{2} + H C l$
$X + N a \to C + H_{2}$
$B + C \to (C_{2} H_{5})_{2} O + N a C l$

Then A and X respectively are

C_{2} H_{6} + C l_{2} \to H C l + C_{2} H_{5} C l

x N a_{2} H A s O_{3} + y N a B r O_{3} + z H C l \to N a B r + H_{3} A s O_{4} + N a C l

x, y, z

N a_{2} H A s O_{3}, N a B r O_{3}, H C l

x + y + z

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