$C_{2} H_{2} 2 m o l e s - --- \to N a A C H_{3} I - ---- \to (E x c e s s) B H_{2} - ------ \to P d + B a S O_{4} C$ \

When 'C' is oxidized with acidified $K M n O_{4}$ , th eproduct formed is

CH₃CH₂OH

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CH₃CHO

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CH₃COCH₃

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CH₃COOH

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Solution

The correct option is D
CH₃COOH

B = 2 - butyne; C = 2 - butene

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