$C + 2 H_{2} S O_{4} ⟶ C O_{2} + 2 H_{2} O + 2 S O_{2}$
Calculate the mass of carbon oxidized by 49 gm of sulphuric acid.

1.5 g

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3 g

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49 g

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16 g

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Solution

The correct option is B 3 g
$C + 2 H_{2} S O_{4} ⟶ C O_{2} + 2 H_{2} O + 2 S O_{2}$
$1$ $2$
$12$ g $(98 \times 2)$ g
So, mass of C oxidized by 49 gm $H_{2} S O 4 = 12 \times \frac{49}{196} = 3 g$ .

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Similar questions

C + 2 H_{2} {S O}_{4} \to {C O}_{2} + {2 H}_{2} O + 2 {S O}_{2}

From the equation:

C + 2H₂SO₄ → CO₂+ 2H₂O +2SO₂

Calculate:

The mass of carbon oxidized by 49 g of sulphuric acid (C = 12; relative molecular mass of sulphuric acid = 98).

C + 2 H_{2} S O_{4} ⟶ C O_{2} + 2 H_{2} O + 2 S O_{2}

S O_{2}

H_{2} S O_{4}

2 A g + 2 H_{2} S O_{4} \to A g_{2} S O_{4} + 2 H_{2} O

S + 2 H_{2} S O_{4} \to 3 S O_{2} + 2 H_{2} O

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