$. . . . . . . . C_{2} H_{4} (g) + . . . . . . . . O_{2} (g) \to . . . . C O_{2} (g) + . . . . . . H_{2} O (l)$ .
What is the coefficient of oxygen if the equation for the reaction is balanced with whole-number coefficients?

1

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Solution

The correct option is C $3$
The unbalanced chemical equation is
$C_{2} H_{4} (g) + O_{2} (g) \to C O_{2} (g) + H_{2} O (l)$
Balance C atoms.
$C_{2} H_{4} (g) + O_{2} (g) \to 2 C O_{2} (g) + H_{2} O (l)$
Balance H atoms.
$C_{2} H_{4} (g) + O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l)$
Balance O atoms.
$C_{2} H_{4} (g) + 3 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l)$
This is balanced chemical equation. The coefficient of oxygen is 3.

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