C^-4 is unstable, because it would be very difficult for 6 protons to hold 10 electrons. True or false.

True

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False

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Solution

The correct option is A
True

In case C^-4, the number of electrons in the outer most orbit is 8. Thus the total number of electrons including 2 electrons in the inner orbit is 10. But the number of protons still remains the same .i.e. 6. Thus it becomes difficult for 6 electrons to hold back 10 electrons.

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C^{4 -}

is unstable because it would be very difficult for 6 protons to hold 10 electrons.

C^{- 4}

is unstable because it would be very difficult for 6 protons to hold 10 electrons.

In a $C^{- 4}$ , its very difficult for 6 protons to hold 10 electrons.

$\begin{matrix} C o l u m n A & C o l u m n B 1 & C^{- 4} i s h i g h l y u n s t a b l e b e c a u s e & A & I t w o u l d b e d i f f i c u l t f o r c a r b o n w i t h s i x p r o t o n s i n i t s n u c l e u s t o h o l d o n j u s t t w o e l e c t r o n s . 2 & C^{+ 4} i s a c h i e v e d b y & B & G a i n i n g 4 e l e c t r o n s t o i t s o u t e r m o s t o r b i t 3 & C^{+ 4} i s h i g h l y u n s t a b l e b e c a u s e & C & L o o s i n g 4 v a l e n c e e l e c t r o n s 4 & C^{- 4} i s a c h i e v e d b y & D & I t i s d i f f i c u l t f o r t h e n u c l e u s w i t h s i x p r o t o n s t o h o l d o n t e n e l e c t r o n s, i . e . f o u r e x t r a e l e c t r o n s \end{matrix}$

Can the side lengths 3cm, 4cm, 10cm form a triangle? State with true or false.

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C-4 is unstable, because it would be very difficult for 6 protons to hold 10 electrons. True or false.

C^-4 is unstable, because it would be very difficult for 6 protons to hold 10 electrons. True or false.