Question

$C_4{H}_8$ can exhibit the following isomerism:

• A. positional isomerism
• B. ring chain isomerism
• C. geometrical isomerism
• D. All of the above

Answer 1

The correct option is D All of the above

For a compound with molecular formula $C_c{H}_h{X}_x{N}_n{O}_o$
$\text{Degree of unsaturation}=(c+1)-\frac{h}{2}-\frac{x}{2}+\frac{n}{2}$
Where, X = Halogen
c=number of carbon atom
h=number of hydrogen atom
n=number of nitrogen atom
o=number of oxygen atom
In $C_4{H}_8$
$\text{Degree of unsaturation}=(4+1)-\frac{8}{2}=1$
Compound has one degree of unsaturation, it means a compound has either one double bond or one ring.

Hence, $C_4{H}_8$ can show all of the above given isomerism.