$C_{6} H_{14 (l)} + O_{2 (g)} \to C O_{2 (g)} + H_{2} O_{(l)}$
When the equation for the reaction represented above is balanced and the coefficient are reduced to the lowest whole number terms, the coefficient for $H_{2} O$ is:

1

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2

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6

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14

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Solution

The correct option is D $14$
The balanced equation can be written as
$2 C_{6} H_{14} + 19 O_{2} \to 12 C O_{2} + 14 H_{2} O$
Thus the coefficient of $H_{2} O$ is 14.
Option D is the correct answer.

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