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Byju's Answer
Standard XII
Chemistry
Preparation of Alcohols from Carbonyl Compounds
C6H5-CH=CHCHO...
Question
C
6
H
5
−
C
H
=
C
H
C
H
O
X
→
C
6
H
5
C
H
=
C
H
C
H
2
O
H
In the above sequence X can be:
A
H
2
/
N
i
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B
N
a
B
H
4
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C
K
2
C
r
2
O
7
/
H
+
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D
Both (1) and (2)
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Solution
The correct option is
B
N
a
B
H
4
N
a
B
H
4
and
L
i
A
l
H
4
attacks only carbonyl group and reduce it into alcohol group. They do not attack on double bond.
C
6
H
5
−
C
H
=
C
H
C
H
O
c
i
n
n
a
m
i
c
a
l
d
e
h
y
d
e
N
a
B
H
4
−
−−−
→
C
6
H
5
−
C
H
=
C
H
.
C
H
2
O
H
c
i
n
n
a
m
i
c
a
l
c
o
h
o
l
X is
N
a
B
H
4
Option B
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Similar questions
Q.
C
6
H
5
−
C
H
=
C
H
C
H
O
X
−
→
C
6
H
5
C
H
=
C
H
C
H
2
O
H
In this sequence, reagent ‘X’ can be:
Q.
In the given reaction
C
6
H
5
C
H
=
C
H
−
C
H
O
[
x
]
−
→
C
6
H
5
−
C
H
=
C
H
−
C
H
2
O
H
.
X will be
Q.
Consider the following carbocations :
(I)
C
6
H
5
C
H
+
2
(II)
C
6
H
5
C
H
2
−
C
H
+
2
(III)
C
6
H
5
−
C
H
+
−
C
H
3
(IV)
C
6
H
5
C
+
(
C
H
3
)
2
The correct sequence for the stability of these is:
Q.
In the reaction:
C
6
H
5
C
H
O
+
C
6
H
5
N
H
2
→
[
A
]
N
i
/
H
2
−
−−−
→
Δ
[
B
]
The product [B] is:
Q.
C
6
H
5
−
C
H
=
C
H
−
C
H
O
→
C
6
H
5
−
C
H
2
−
C
H
2
−
C
H
2
O
H
in the presence of X,what will be X:
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