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Question

C6H5CH=CHCHOXC6H5CH=CHCH2OH
In the above sequence X can be:

A
H2/Ni
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B
NaBH4
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C
K2Cr2O7/H+
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D
Both (1) and (2)
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Solution

The correct option is B NaBH4
NaBH4 and LiAlH4 attacks only carbonyl group and reduce it into alcohol group. They do not attack on double bond.

C6H5CH=CHCHOcinnamic aldehydeNaBH4−−−C6H5CH=CH.CH2OHcinnamic alcohol

X is NaBH4

Option B

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